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5x^2+90x=144
We move all terms to the left:
5x^2+90x-(144)=0
a = 5; b = 90; c = -144;
Δ = b2-4ac
Δ = 902-4·5·(-144)
Δ = 10980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10980}=\sqrt{36*305}=\sqrt{36}*\sqrt{305}=6\sqrt{305}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-6\sqrt{305}}{2*5}=\frac{-90-6\sqrt{305}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+6\sqrt{305}}{2*5}=\frac{-90+6\sqrt{305}}{10} $
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